Infinitesimal dipole segment of length d z. Radiation from the antenna by converting from charges andĮquation 2.136 from the derivation of Larmor’sĬan be applied to yield the d E ⊥ contributed by each In the antenna wires, so Larmor’s formula can be used to calculate the With the implicit understanding that only the real part of I So the driving current can be rewritten as Is computationally convenient to replace the trigonometric functionĬos ( ω t ) with its complex exponential equivalentĮ - i ω t = cos ( ω t ) - i sin ( ω t ) ,
Where I 0 is the peak current going into each half of the dipole. The radiation from a dipole depends on the transmitterįrequency, so consider a sinusoidal driving current I with (a transmitter), the current going into the bottom conductor is 180ĭegrees out of phase with the current going into the topĬonductor. One wavelength λ) dipole antenna, which is shown inįigure 3.1 as two collinear conductors (e.g., wires orĭriven at the small gap between them by an oscillating current source The simplest antenna is a short (total length l much smaller than
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